Page 516 **Exercise Set 8.1** 1. As in Example 8.1.2, the **congruence modulo $2$** relation $E$ is defined from $\mathbb{Z}$ to $\mathbb{Z}$ as follows: For every ordered pair $(m, n) \in \mathbb{Z} \times \mathbb{Z}$, $$ m E n \Leftrightarrow m - n \text{ is even} $$ a. Is $0 E 0$? Is $5 E 2$? Is $(6, 6) \in E$? Is $(-1, 7) \in E$? _$0 E 0$:_ Yes, $0 - 0 = 0$, and $0$ is even. _$5 E 2$:_ No, $5 - 2 = 3$, and $3$ is not even. _$(6, 6) \in E$:_ Yes, $6 - 6 = 0$, and $0$ is even. _$(-1, 7) \in E$:_ Yes, $-1 - 7 = -8$, and $-8$ is even. b. Prove that for any even integer $n$, $n E 0$. **Proof:** Suppose $n \in 2\mathbb{Z}$, where $2\mathbb{Z}$ is the set of all even integers. By the definition for even, this means that $n = 2k$ for some integer $k$. By the definition for $E$, $n E 0$ if, and only if $n - 0$ is even. By substitution for $E$: $$ n - 0 = 2k - 0 $$ $$ = 2k $$ By the definition for even, this means that $n - 0$ is even, and therefore $n E 0$ is true. Q.E.D. 2. Prove that for all integers $m$ and $n$, $m - n$ is even if, and only if, both $m$ and $n$ are even or both $m$ and $n$ are odd. _Hint:_ To prove a statement of the form $p \Leftrightarrow (q \vee r)$, you need to prove both (1)$p \to (q \vee r)$ and (2) $(q \vee r) \to p$. The easiest way to prove $p \to (q \vee r)$ is to prove the logically equivalent statement form $(p \wedge \neg q) \to r$. And the easiest way to prove $(q \vee r) \to p$ is to prove the logically equivalent statement form $(q \to p) \wedge (r \to p)$. In this case, suppose $m$ and $n$ are any integers, and let $p$ be "$m - n$ is even," let $q$ be "both $m$ and $n$ are even," and let $r$ be "both $m$ and $n$ are odd." **Proof:** Suppose $m$ and $n$ are any integers. To prove that for all integers $m$ and $n$, $m - n$ is even if, and only if, both $m$ and $n$ are even or both $m$ and $n$ are odd, it must be shown first that if $m - n$ is even, then both $m$ and $n$ are even or both $m$ and $n$ are odd, then it must be shown second that if both $m$ and $n$ are even or both $m$ and $n$ are odd, then $m - n$ is even. _Proof (first):_ Suppose $m - n$ is even. To prove that both $m$ and $n$ must be even or both $m$ and $n$ must be odd, all cases for where $m$ is even or odd and where $n$ is even or odd must be considered. _Case (both $m$ and $n$ are even):_ Since both $m$ and $n$ are even, this means that $m = 2k$ and $n = 2p$ for some integers $k$ and $p$. Then: $$ m - n = 2k - 2p $$ $$ = 2(k - p) $$ Now, $k - p$ is an integer by the subtraction of integers. Therefore, by the definition of even, $m - n$ is even. _Case (both $m$ and $n$ are odd):_ Since both $m$ and $n$ are odd, this means that $m = 2k + 1$ and $n = 2p + 1$ for some integers $k$ and $p$. Then: $$ m - n = (2k + 1) - (2p + 1) $$ $$ = 2k + 1 - 2p - 1 $$ $$ = 2k - 2p $$ $$ = 2(k - p) $$ Now, $k - p$ is an integer by the subtraction of integers. Therefore, by the definition of even, $m - n$ is even. _Case ($m$ is even and $n$ is odd):_ Since $m$ is even and $n$ is odd, $m = 2k$ and $n = 2p + 1$ for some integers $k$ and $p$. Then: $$ m - n = 2k - (2p + 1) $$ $$ = 2k - 2p - 1 $$ $$ = 2(k - p) - 1 $$ Now, $k - p$ is an integer by the subtraction of integers. Thus, by the definition of odd, $m - n$ is odd, but by the supposition, $m - n$ is even. This is a contradiction. _Case ($m$ is odd and $n$ is even):_ Since $m$ is odd and $n$ is even, $m = 2k + 1$ and $n = 2p$ for some integers $k$ and $p$. Then: $$ m - n = (2k + 1) - 2p $$ $$ = 2k - 2p + 1 $$ $$ = 2(k - p) + 1 $$ Now, $k - p$ is an integer by the subtraction of integers. Thus, by the definition of odd, $m - n$ is odd, but by the supposition, $m - n$ is even. This is a contradiction. _Conclusion:_ It can be concluded based off of all cases that when both $m$ and $n$ are even or both $m$ and $n$ are odd, $m - n$ is even. _Proof (second):_ Suppose both $m$ and $n$ are both even or are both odd. In order to prove $m - n$ is even, both cases must be considered. _Case (both $m$ and $n$ are even):_ Since both $m$ and $n$ are even, $m = 2k$ and $n = 2p$ for some integers $k$ and $p$. Then: $$ m - n = 2k - 2p $$ $$ = 2(k - p) $$ Now, $k - p$ is an integer by the subtraction of integers. Therefore, by the definition of even, $m - n$ is even. _Case (both $m$ and $n$ are odd):_ Since both $m$ and $n$ are odd, $m = 2k + 1$ and $n = 2p + 1$ for some integers $k$ and $p$. Then: $$ m - n = (2k + 1) - (2p + 1) $$ $$ = 2k + 1 - 2p - 1 $$ $$ = 2k - 2p $$ $$ = 2(k - p) $$ Now, $k - p$ is an integer by the subtraction of integers. Therefore, by the definition of even, $m - n$ is even. _Conclusion:_ In both cases, $m - n$ is even. Therefore it can be concluded that if both $m$ and $n$ are even or if both $m$ and $n$ are odd, then $m - n$ is even. 3. The **congruence modulo $3$** relation, $T$, is defined from $\mathbb{Z}$ to $\mathbb{Z}$ as follows: For all integers $m$ and $n$, $$ m T n \Leftrightarrow 3 | (m - n) $$ a. Is $10 T 1$? Is $1 T 10$? Is $(2, 2) \in T$? Is $(8, 1) \in T$? _$10 T 1$:_ Yes, since $3 | (10 - 1) = 3 | 9 = 3$ _$1 T 10$:_ Yes, since $3 | (1 - 10) = 3 | -9 = -3$ _$(2, 2) \in T$:_ Yes, since $3 | (2 - 2) = 3 | 0 = 0$ _$(8, 1) \in T$:_ No, since $3 | (8 - 1) = 3 \cancel{|} 7$. b. List five integers $n$ such that $n T 0$. $3$; $6$, $9$, $12$, $15$ c. List five integers $n$ such that $n T 1$. $4$; $7$, $10$, $13$, $16$ d. List five integers $n$ such that $n T 2$. $$ 3 | (n - 2) $$ $5$, $8$, $11$, $14$, $17$ e. Make and prove a conjecture about which integers are related by $T$ to $0$, which integers are related to $T$ to $1$, and which integers are related to $T$ to $2$. _Hint:_ All integers of the form $3k + 1$, for some integer $k$, are related by $T$ to $1$. **Conjecture:** All integers of the form $3k$, for some integer $k$, are related by $T$ to $0$. All integers of the form $3p + 1$, for some integer $p$, are related by $T$ to $1$. All integers of the form $3m + 2$, for some integer $m$, are related to $T$ by $2$. 4. Define a relation $P$ on $\mathbb{Z}$ as follows: For every ordered pair $(m, n) \in \mathbb{Z} \times \mathbb{Z}$, $$ m P n \Leftrightarrow m \text{ and } n \text{ have a common prime factor} $$ a. Is $15 P 25$? Yes, because both $15$ and $25$ are divisible by $5$, which is a prime factor. b. Is $22 P 27$? No, because $22$ and $27$ have no common divisors. c. Is $0 P 5$? Yes, because both $0$ and $5$ are divisible by $5$, which is a prime factor. d. Is $8 P 8$? Yes, because both $8$ and $8$ are divisible by $2$, which is a prime factor. 5. Let $X = \{a, b, c\}$. Recall that $\mathscr{P}(X)$ is the power set of $X$. Define a relation $\mathbf{S}$ on $\mathscr{P}(X)$ as follows: For all sets $A$ and $B$ in $\mathscr{P}(X)$, $$ A \mathbf{S}B \Leftrightarrow A \text{ has the same number of elements as } B $$ a. Is $\{a, b\} \mathbf{S} \{b, c\}$? Yes, since both $\{a, b\}$ and $\{b, c}$ have the same number of elements, namely $2$ elements. b. Is $\{a\} \mathbf{S} \{a, b\}$? No, since $\{a\}$ has $1$ element and $\{a, b\}$ has $2$ elements, and $1 \neq 2$. c. Is $\{c\} \mathbf{S} \{b\}$? Yes, since both $\{c\}$ and $\{b\}$ have the same number of elements, namely $1$ element. 6. Let $X = \{a, b, c\}$. Recall that $\mathscr{P}(X)$ as follows: For all sets $A$ and $B$ in $\mathscr{P}(X)$, $$ A \mathbf{J} B \Leftrightarrow A \cap B \neq \emptyset $$ a. Is $\{a\} \mathbf{J} \{c\}$? No, since $\{a\} \cap \{\c} = \emptyset$. b. Is $\{a, b\} \mathbf{J} \{b, c\}$? Yes, since $\{a, b\} \cap \{b, c\} = \{b\} \neq \emptyset$. c. Is $\{a, b} \mathbf{J} \{a, b, c\}$? Yes, since $\{a, b\} \cap \{a, b, c\} = \{a, b\} \neq \emptyset$. 7. Define a relation $R$ on $\mathbb{Z}$ as follows: For all integers $m$ and $n$, $$ m R n \Leftrightarrow 5 | (m^2 - n^2) $$ a. Is $1 R (-9)$? $$ 5 | ((1)^2 - (-9)^2) $$ $$ 5 | (1 - 81) $$ $$ 5 | (-80) = -16 $$ Yes. b. Is $2 R 13$? $$ 5 | ((2)^2 - (13)^2) $$ $$ 5 | (4 - 169) $$ $$ 5 | (-165) = -33 $$ Yes. c. Is $2 R (-8)$? $$ 5 | ((2)^2 - (-8)^2) $$ $$ 5 | (4 - (64)) $$ $$ 5 | (-60) = -12 $$ Yes. d. Is $(-8) R 2$? $$ 5 | (64 - 4) $$ $$ 5 | 60 = 12 $$ Yes. 8. Let $A$ be the set of all strings of _a_'s and _b_'s of length $4$. Define a relation $R$ on $A$ as follows: For every $s, t \in A$, $$ s R t \Leftrightarrow s \text{ has the same first two characters as } t $$ a. Is _abaa_ $R$ _abba_? Yes, since _ab_ is the same first two characters of both _abaa_ and _abba_. b. Is _aabb_ $R$ _bbaa_? No, since _aa_ is the first two characters of _aabb_ and _bb_ is the first same two characters as _bbaa_, it can be concluded that _aabb_ and _bbaa_ do not have the same first two characters. c. Is _aaaa_ $R$ _aaab_? Yes, since _aa_ is the same first two characters of both _aaaa_ and _aaab_. d. Is _baaa_ $R$ _abaa_? No, since _ba_ and _ab_ are the first two characters of _baaa_ and _abaa_ respectively. 9. Let $A$ be the set of all strings of 0's, 1's, and 2's of length $4$. Define a relation $R$ on $A$ as follows: For every $s, t \in A$, $$ s R t \Leftrightarrow \text{ the same of the characters in } s \text{ equals the sum of the characters in } t $$ a. Is 0121 $R$ 2200? $$ 0 + 1 + 2 + 1 = 4 = 2 + 2 + 0 + 0 $$ Yes. b. Is 1011 $R$ 2101? $$ 1 + 0 + 1 + 1 = 3 = \neq 4 = 2 + 1 + 0 + 1 $$ No. c. Is 2212 $R$ 2121? $$ 2 + 2 + 1 + 2 = 7 \neq 6 = 2 + 1 + 2 + 1 $$ No. d. Is 1220 $R$ 2111? $$ 1 + 2 + 2 + 0 = 5 = 2 + 1 + 1 + 1 $$ Yes. 10. Let $A = \{3, 4, 5\}$ and $B = \{4, 5, 6\}$ and let $R$ be the "less than" relation. That is, for every ordered pair $(x, y) \in A \times B$, $$ x R y \Leftrightarrow x < y $$ State explicitly which ordered pairs are in $R$ and $R^{-1}$. $$ R = \{(3, 4), (3, 5), (3, 6), (4, 5), (4, 6), (5, 6) \} $$ $$ R^{-1} = \{(4, 3), (5, 3), (6, 3), (5, 4), (6, 4), (6, 5) \} $$ 11. Let $A = \{3, 4, 5\}$ and $B = \{4, 5, 6\}$ and let $S$ be the "divides" relation. That is, for every ordered pair $(x, y) \in A \times B$, $$ x S y \Leftrightarrow x | y $$ State explicitly which ordered pairs are in $S$ and $S^{-1}$. $$ S = \{(3, 6), (4, 4), (5, 5)\} $$ $$ S^{-1} = \{(6, 3), (4, 4), (5, 5)\} $$ 12. a. Suppose a function $F: X \to Y$ is one-to-one but not onto. Is $F^{-1}$ (the inverse relation for $F$) a function? Explain your answer. No, if $F: X \to Y$ is one-to-one, but not onto, then its inverse relation $F^{-1}: Y \to X$ will have some elements in its domain that have not elements in the co-domain. More formally: $$ \exists y \in Y | (y, x) \notin F^{-1} $$ which means $F^{-1}$ does not satisfy property 1 for being a function. b. Suppose a function $F: X \to Y$ is onto but not one-to-one. Is $F^{-1}$ (the inverse relation for $F$) a function? Explain your answer. No, if $F: X \to Y$ is onto, but not one-to-one, it follows that its inverse relation $F^{-1}: Y \to X$ will have at least one $y \in Y | (y, x_1) \in F^{-1} \wedge (y, x_2) \in F^{-1}$. This violates property 2 of the definition of a function. Draw the directed graphs of the relations defined in 13-18. 13. Define a relation $R$ on $A = \{0, 1, 2, 3\}$ by $R = \{(0, 0), (1, 2), (2, 2)\}$. (Done by hand.) 14. Define a relation $S$ on $B = \{a, b, c, d\}$ by $S = \{(a, b), (a, c), (b, c), (d, d)\}$. (Done by hand.) 15. Let $A = \{2, 3, 4, 5, 6, 7, 8\}$ and define a relation $R$ on $A$ as follows: For every $x, y \in A$, $$ x R y \Leftrightarrow x | y $$ (Done by hand.) 16. Let $A = \{5, 6, 7, 8, 9, 10\}$ and define a relation $S$ on $A$ as follows: For every $x, y \in A$, $$ x S y \Leftrightarrow 2 | (x - y) $$ (Done by hand.) 17. Let $A = \{2, 3, 4, 5, 6, 7, 8\}$ and define a relation $T$ on $A$ as follows: For every $x, y \in A$, $$ x T y \Leftrightarrow 3 | (x - y) $$ (Done by hand.) 18. Let $A = \{0, 1, 3, 4, 5, 6\}$ and define a relation $V$ on $A$ as follows: For every $x, y \in A$, $$ x V y \Leftrightarrow 5 | (x^2 - y^2) $$ (Done by hand.) Exercises 19-20 refer to unions and intersections of relations. Since relations are subsets of Cartesian products, their unions and intersections can be calculated as for any subsets. Given two relations $R$ and $S$ from $A$ to $B$, $$ R \cup S = \{(x, y) \in A \times B | (x, y) \in R \text{ or } (x, y) \in S\} $$ $$ R \cap S = \{(x, y) \in A \times B | (x, y) \in R \text{ and } (x, y) \in S\} $$ 19. Let $A = \{2, 4\}$ and $B = \{6, 8, 10\}$ and define relations $R$ and $S$ from $A$ to $B$ as follows: For every $(x, y) \in A \times B$, $$ x R y \Leftrightarrow x | y \text{ and } x S y \Leftrightarrow y - 4 = x $$ State explicitly which ordered pairs are in $A \times B$, $R$, $S$, $R \cup S$, and $R \cap S$. $$ A \times B = \{(2, 6), (2, 8), (2, 10), (4, 6), (4, 8), (4, 10)\} $$ $$ R = \{(2, 6), (2, 8), (2, 10), (4, 8)\} $$ $$ S = \{(2, 6), (4, 8)\} $$ $$ R \cup S = \{(2, 6), (2, 8), (2, 10), (4, 8)\} = R $$ $$ R \cap S = \{(2, 6), (4, 8)\} = S $$ 20. Let $A = \{-1, 1, 2, 4\}$ and $B = \{1, 2\}$ and define relations $R$ and $S$ from $A$ to $B$ as follows: For every $(x, y) \in A \times B$, $$ x R y \Leftrightarrow |x| = |y| \text{ and } x S y \Leftrightarrow x - y \text{ is even} $$ State explicitly which ordered pairs are in $A \times B$, $R$, $S$, $R \cup S$, and $R \cap S$. $$ A \times B = \{(-1, 1), (-1, 2), (1, 1), (1, 2), (2, 1), (2, 2), (4, 1), (4, 2)\} $$ $$ R = \{(-1, 1), (1, 1), (2, 2)\} $$ $$ S = \{(-1, 1), (1, 1), (2, 2), (4, 2)\} $$ $$ R \cup S = \{(-1, 1), (1, 1), (2, 2), (4, 2)\} = S $$ $$ R \cap S = \{(-1, 1), (1, 1), (2, 2)\} = R $$ 21. Define relations $R$ and $S$ on $\mathbb{R}$ as follows: $$ R = \{(x, y) \in \mathbb{R} \times \mathbb{R} | x < y\} \text{ and } S = \{(x, y) \in \mathbb{R} \times \mathbb{R} | x = y\}$$ That is, $R$ is the "less than" relation and $S$ is the "equals" relation on $\mathbb{R}$. Graph $R$, $S$, $R \cup S$, and $R \cap S$ in the Cartesian plane. Think on this and then see appendix b (Page 975). 22. Define relations $R$ and $S$ on $\mathbb{R}$ as follows: $$ R = \{(x, y) \in \mathbb{R} \times \mathbb{R} | x^2 + y^2 = 4\} \text{ and } S = \{(x, y) \in \mathbb{R} \times \mathbb{R} | x = y\} $$ Graph $R$, $S$, $R \cup S$, and $R \cap S$ in the Cartesian plane. 23. Define relations $R$ and $S$ on $\mathbb{R}$ as follows: $$ R = \{(x, y) \in \mathbb{R} \times \mathbb{R} | y = |x|\} \text{ and } S = \{(x, y) \in \mathbb{R} \times \mathbb{R} | y = 1\} $$ Graph $R$, $S$, $R \cup S$, and $R \cap S$ in the Cartesian plane. $R$ is a circle about the origin (with intersections along the axis along $(-2, 0), (0, 2), (2, 0), (-2, 0)$). $S$ is a straight diagonal line ascending from the left to the right, intersecting the origin $(0, 0)$. $R \cup S$ is just the two graphs drawn together. $R \cap S$ is only the two points along which the two graphs intersect. (Done by hand.) 24. In Example 8.1.7 consider the query SELECT Patient_ID#, Name FROM S WHERE Primary_Diagnosis = X. The response query is the projection onto the first two coordinates of the intersection of the database with the set $A_1 \times A_2 \times A_3 \times \{X\}$. a. Find the result of the query SELECT Patient_ID#, Name FROM S WHERE Primary_Diagnosis = pneumonia. (574329, Tak Kurosawa), (011985, John Schmidt) b. Find the result of the query SELECT Patient_ID#, Name FROM S WHERE Primary_Diagnosis = appendicitis. (466581, Mary Lazars), (778400, Jamal Baskers) --- Page 526 **Exercise Set 8.2** In 1-8, a number of relations are defined on the set $A = \{0, 1, 2, 3\}$. For each relation: a. Draw the directed graph. b. Determine whether the relation is reflexive. c. Determine whether the relation is symmetric. d. Determine whether the relation is transitive. Give a counterexample in each case in which the relation does not satisfy one of the properties. 1. $R_1 = \{(0, 0), (0, 1), (0, 3), (1, 1), (1, 0), (2, 3), (3, 3)\}$ 2. $R_2$ = \{(0, 0), (0, 1), (1, 1), (1, 2), (2, 2), (2, 3)\} 3. $R_3 = \{(2, 3), (3, 2)\}$ 4. $R_4 = \{(1, 2), (2, 1), (1, 3), (3, 1)\}$ 5. $R_5 = \{(0, 0), (0, 1), (0, 2), (1, 2)\}$ 6. $R_6 = \{(0, 1), (0, 2)\}$ 7. $R_7 = \{(0, 3), (2, 3)\}$ 8. $R_8 = \{(0, 0), (1, 1)\}$ In 9-33, determine whether the given relation is reflexive, symmetric, transitive, or none of these. Justify your answers. 9. $R$ is the "greater than or equal to" relation on the set of real numbers: For every $x, y \in \mathbb{R}$, $x R y \Leftrightarrow x \geq y$. 10. $C$ is the circle relation on the set of real numbers: For every $x, y \in \mathbb{R}, x C y \Leftrightarrow x^2 + y^2 = 1$. 11. $D$ is the relation defined on $\mathbb{R}$ as follows: For every $x, y \in \mathbb{R}, x D y \Leftrightarrow xy \geq 0$. 12. $E$ is the congruence modulo $4$ relation on $\mathbb{Z}$: For every $m, n \in \mathbb{Z}, m E n \Leftrightarrow 4 | (m - n)$. 13. $F$ is the congruence modulo $5$ relation on $\mathbb{Z}$: For every $m, n \in \mathbb{Z}, m F n \Leftrightarrow 5 | (m - n)$. 14. $O$ is the relation defined on $\mathbb{Z}$ as follows: For every $m, n \in \mathbb{Z}, m O n \Leftrightarrow m - n \text{ is odd}$. 15. $D$ is the "divides" relation on $\mathbb{Z}^+$: For all positive integers $m$ and $n$, $m D n \Leftrightarrow m | n$. 16. $A$ is the "absolute value" relation on $\mathbb{R}$: For all real numbers $x$ and $y$, $x A y \Leftrightarrow |x| = |y|$. 17. Recall that a prime number is an integer that is greater than $1$ and has no positive integer divisors other than $1$ and itself. (In particular, $1$ is not prime.) A relation $P$ is defined on $\mathbb{Z}$ as follows: For every $m, n \in \mathbb{Z}, m P n \Leftrightarrow \exists \text{ a prime number } p \text{ such that } p | m \text{ and } p | n$. 18. Define a relation $Q$ on $\mathbb{R}$ as follows: For all real numbers $x$ and $y$, $x Q y \Leftrightarrow x - y$ is rational. 19. Define a relation $I$ on $\mathbb{R}$ as follows: For all real numbers $x$ and $y$, $x I y \Leftrightarrow x - y$ is irrational. 20. Let $X = \{a, b, c\}$ and $\mathscr{P}(X)$ be the power set of $X$ (the set of all subsets of $X$). A relation $\mathbf{E}$ is defined on $\mathscr{P}(X)$ as follows: For every $A, B \in \mathscr{P}(X), A \mathbf{E} B \Leftrightarrow \text{ the number of elements in } A \text{ equals the number of elements in } B$. 21. Let $X = \{a, b, c\}$ and $\mathscr{P}(X)$ be the power set of $X$. A relation $\mathbf{L}$ is defined on $\mathscr{P}(X)$ as follows: For every $A, B \in \mathscr{P}(X), A \mathbf{L} B \Leftrightarrow \text{ the number of elements in } A \text{ is less than the number of elements in } B$. 22. Let $X = \{a, b, c\}$ and $\mathscr{P}(X)$ be the power set of $X$. A relation $\mathbf{N}$ is defined on $\mathscr{P}(X)$ as follows: For every $A, B \in \mathscr{P}(X), A \mathbf{N} B \Leftrightarrow \text{ the number of elements in } A \text{ is not equal to the number of elements in } B$. 23. Let $X$ be a nonempty set and $\mathscr{P}(X)$ the power set of $X$. Define the "subset" relation $\mathbf{S}$ on $\mathscr{P}(X)$ as follows: For every $A, B \in \mathscr{P}(X), A \mathbf{S} B \Leftrightarrow A \subseteq B$. 24. Let $X$ be a nonempty set and $\mathscr{P}(X)$ the power set of $X$. Define the "not equal to" relation $\mathbf{U}$ on $\mathscr{P}(X)$ as follows: For every $A, B \in \mathscr{P}(X), A \mathbf{U} B \Leftrightarrow A \neq B$. 25. Let $A$ be the set of all strings of _a_'s and _b_'s of length $4$. Define a relation $R$ on $A$ as follows: For every $s, t \in A, s R t \Leftrightarrow s \text{ has the same first two characters as } t$. 26. Let $A$ be the set of all strings of 0's, 1's, and 2's that have length 4 and for which the sum of the characters in the string is less than or equal to 2. Define a relation $R$ on $A$ as follows: For every $s, t \in A, s R t \Leftrightarrow \text{ the sum of the characters of } s \text{ equals the sum of the characters of } t$. 27. Let $A$ be the set of all English statements. A relation $\mathbf{I}$ is defined on $A$ as follows: For every $p, q \in A$, $$ p \mathbf{I} q \Leftrightarrow p \to q \text{ is true} $$ 28. Let $A = \mathbb{R} \times \mathbb{R}$. A relation $\mathbf{S}$ is defined on $A$ as follows: For every $(x_1, y_1)$ and $(x_2, y_2)$ in $A$, $$ (x_1, y_2) \mathbf{S} (x_2, y_2) \Leftrightarrow x_1 = x_2 $$ 29. Let $A = \mathbb{R} \times \mathbb{R}$. A relation $\mathbf{S}$ is defined on $A$ as follows: For every $(x_1, y_1)$ and $(x_2, y_2)$ in $A$, $$ (x_1, y_2) \mathbf{S} (x_2, y_2) \Leftrightarrow y_1 = y_2 $$ 30. Let $A$ be the "punctured plane"; that is, $A$ is the set of all points in the Cartesian plane except the origin $(0, 0)$. A relation $R$ is defined on $A$ as follows: For every $p_1$ and $p_2$ in $A$, $p_1 R p_2 \Leftrightarrow p_1 \text{ and } p_2 \text{ lie on the same half line emanating from the origin}$. 31. Let $A$ be the set of people living in the world today. A relation $R$ is defined on $A$ as follows: For all people $p$ and $q$ in $A$, $$ p R q \Leftrightarrow p \text{ lives within 100 miles of } q $$ 32. Let $A$ be the set of all lines in the plane. A relation $R$ is defined on $A$ as follows: For every $l_1$ and $l_2$ in $A$, $l_1 R l_2 \Leftrightarrow l_1 \text{ is parallel to } l_2$. (Assume that a line is parallel to itself.) 33. Let $A$ be the set of all lines in the plane. A relation $R$ is defined on $A$ as follows: For every $l_1$ and $l_2$ in $A$, $$ l_1 R l_2 \Leftrightarrow l_1 \text{ is perpendicular to } l_2 $$ In 34-36, assume that $R$ is a relation on a set $A$. Prove or disprove each statement. 34. If $R$ is reflexive, then $R^{-1}$ is reflexive. 35. If $R$ is symmetric, then $R^{-1}$ is symmetric. 36. If $R$ is transitive, then $R^{-1}$ is transitive. In 37-42, assume that $R$ and $S$ are relations on a set $A$. Prove or disprove each statement. 37. If $R$ and $S$ are reflexive, is $R \cap S$ reflexive? Why? 38. If $R$ and $S$ are symmetric, is $R \cap S$ symmetric? Why? 39. If $R$ and $S$ are transitive, is $R \cap S$ transitive? Why? 40. If $R$ and $S$ are reflexive, is $R \cup S$ reflexive? Why? 41. If $R$ and $S$ are symmetric, is $R \cup S$ symmetric? Why? 42. If $R$ and $S$ are transitive, is $R \cup S$ transitive? Why? In 43-50, the following definitions are used: A relation on a set $A$ is defined to be irreflexive if, and only if, for every $x \in A, x \cancel{R} x$; asymmetric if, and only if, for every $x, y \in A$ if $x R y$ then $y \cancel{R} x$; intransitive if, and only if, for every $x, y, z \in A$, if $x R y$ and $y R z$ then $x \cancel{R} z$. For each of the relations in the referenced exercise, determine whether the relation is irreflexive, asymmetric, intransitive, or none of these. 43. Exercise 1 44. Exercise 2 45. Exercise 3 46. Exercise 4 47. Exercise 5 48. Exercise 6 49. Exercise 7 50. Exercise 8 In 51-53, $R$, $S$, and $T$ are relations defined on $A = \{0, 1, 2, 3\}$. 51. Let $R = \{(0, 1), (0, 2), (1, 1), (1, 3), (2, 2), (3, 0)\}$. Find $R^t$, the transitive closure of $R$. 52. Let $S = \{(0, 0), (0, 3), (1, 0), (1, 2), (2, 0), (3, 2)\}$. Find $S^t$, the transitive closure of $S$. 53. Let $T = \{(0, 2), (1, 0), (2, 3), (3, 1)\}$. Find $T^t$, the transitive closure of $T$. 54. Write a computer algorithm to test whether a relation $R$ defined on a finite set $A$ is reflexive, where $$ A = \{a[1], a[2], \dots, a[n]\} $$ 55. Write a computer algorithm to test whether a relation $R$ defined on a finite set $A$ is symmetric, where $$ A = \{a[1], a[2], \dots, a[n]\} $$ 56. Write a computer algorithm to test whether a relation $R$ defined on a finite set $A$ is transitive, where $$ A = \{a[1], a[2], \dots, a[n]\} $$