🚧 Started 3.2
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- "$\forall x, r(x)$ **only if** $s(x)$" means
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- "$\forall x, r(x)$ **only if** $s(x)$" means
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"$\forall x, \text{ if } \neg s(x) \text{ then } \neg r(x)$" or, equivalently,
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"$\forall x, \text{ if } \neg s(x) \text{ then } \neg r(x)$" or, equivalently,
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"$\forall x, \text{ if } r(x) \text{ then } s(x)$."
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"$\forall x, \text{ if } r(x) \text{ then } s(x)$."
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---
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Page 156
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**Interpreting Statements with Two Different Quantifiers**
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If you want to establish the truth of a statement of the form
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$$ \forall x \text{ in } D, \exists y \text{ in } E \text{ such that } P(x, y) $$
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your challenge is to allow someone else to pick whatever element $x$ in $D$ they
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wish and then you must find an element $y$ in $E$ that "works" for that
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particular $x$.
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If you want to establish the truth of a statement of the form
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$$ \exists x \text{ in } D \text{ such that } \forall y \text{ in } E, P(x, y) $$
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your job is to find one particular $x$ in $D$ that will "work" no matter what
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$y$ in $E$ anyone might choose to challenge you with.
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---
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**Negations of Statements with Two Different Quantifiers**
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$\neg(\forall x \text{ in } d, \exists y \text{ in } E \text{ such that } P(x, y)) \equiv \exists x \text{ in } D \text{ such that } \forall y \text{ in } E, \neg P(x, y)$
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$\neg(\exists x \text{ in } D \text{ such that } \forall y \text{ in } E, P(x, y)) \equiv \forall x \text{ in } D, \exists y \text{ in } E \text{ such that } \neg P(x, y)$
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@ -1 +1 @@
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154
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165
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