🚧 Mid of 8.4

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tomit4 2026-08-23 02:19:22 -07:00
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@ -669,6 +669,74 @@ $$ a^m \equiv [(a \mod n)^m](\mod n) $$
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**Example 8.4.4 Computing $a^k \mod n$ When $k$ is a Power of $2$**
Find $144^4 \mod 713$.
**Solution**
Use property (8.4.1) to write $144^4 = (144^2)^2$. Then
$$ 144^4 \mod 713 = (144^2)^2 \mod 713 $$
$$ = (144^2 \mod 713)^2 \mod 713 $$
$$ = (20736 \mod 713)^2 \mod 713 \text{ because } 144^2 = 20736 $$
$$ = 59^2 \mod 713 \text{ because } 20736 \mod 713 = 59 $$
$$ = 3481 \mod 713 \text{ because } 59^2 = 3481 $$
$$ = 629 \text{ because } 3481 \mod 713 = 629 $$
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**Example 8.4.5 Computing $a^k \mod n$ When $k$ is Not a Power of $2$**
Find $12^{43} \mod 713$.
**Solution**
First write the exponent as a sum of powers of $2$:
$$ 43 = 2^5 + 2^3 + 2 + 1 = 32 + 8 + 2 + 1 $$
Next compute $12^{2^k}$ for $k = 0, 1, 2, 3, 4, \text { and } 5$.
$$ 12 \mod 713 = 12 $$
$$ 12^2 \mod 713 = 144 $$
$$ 12^4 \mod 713 = 144^2 \mod 713 = 59 \text{ by Example 8.4.4} $$
$$ 12^8 \mod 713 = 59^2 \mod 713 = 629 \text{ by Example 8.4.4} $$
$$ 12^{16} \mod 713 = 629^2 \mod 713 = 639 \text{ by the method of Example 8.4.4} $$
$$ 12^{32} \mod 713 = 639^2 \mod 713 = 485 \text{ by the method of Example 8.4.4} $$
By property (8.4.2),
$$ 12^{43} = 12^{32 + 8 + 2 + 1} = 12^{32} \cdot 12^8 \cdot 12^2 \cdot 12^1 $$
Thus, by Corollary 8.4.4,
$$ 12^{43} \mod 713 = \{(12^{32} \mod 713) \cdot (12^8 \mod 713) \cdot (12^2 \mod 713) \cdot (12 \mod 713)\} \mod 713 $$
By substitution,
$$ 12^{43} \mod 713 = (485 \cdot 629 \cdot 144 \cdot 12) \mod 713 $$
$$ = 527152320 \mod 713 $$
$$ = 48 $$
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**Definition**