🚧 Setup for reading/practice/additional exercises

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# 1.5.8 Additional Exercises
1.
Q: Prove that for any two sets $A$ and $B$, $A \subseteq B$ if and only if
$A \cup B = B$.
A:
2.
Q: The **intersection** of sets $A$ and $B$, denoted $A \cap B$, is the set of
all elements that are in both $A$ and $B$.
Prove that for any two sets $A$ and $B$, $A \subseteq B$ if and only if
$A \cap B = A$.
A:
3.
Q: Prove that for any sets $A$, $B$, and $C$, if $A \cup B \subseteq C$, then
$A \subseteq C$ and $B \subseteq C$.
A:
4.
Q: Prove that for any sets $A$, $B$, and $C$, if $A \subseteq C$ and
$B \subseteq C$, then $A \cup B \subseteq C$.
A:
5.
Q: The **difference** of sets $A$ and $B$, written $A$ \ $B$, is the set of all
elements that are in $A$ but not in $B$.
The **empty set**, written $\emptyset$, is the set that contains no elements.
Prove that if $A$ \ $B = A$ then $A \cap B = \emptyset$.
A:
6.
Q: Prove that if $A$ \ $B = B$ \ $A$ then $A = B$.
A:
7.
Q: Let $f:X \to Y$ be a function, and let $A$ and $B$ be subsets of $X$.
(a) Prove that $f(A \cap B) \subseteq f(A) \cap f(B)$.
(b) Find an example of a function and two sets $A$ and $B$ such that
$f(A \cap B) \neq f(A) \cap f(B)$.
A:
8.
Q: Let $f: X \to Y$ be a function, and let $A$ and $B$ be subsets of $X$.
(a) Prove that $f(A \cup B) \subseteq f(A) \cup f(B)$.
(b) Prove that $f(A) \cup (B) \subseteq f(A \cup B)$
\(c\) What can you conclude from the two proofs above?
A:
9.
Q: Given a function $f: X \to Y$ and a set $B \subseteq Y$, we define the
**inverse image** of $B$ under $f$ as the set
$f^{-1}(B) = \{x \in X: f(x) \in B\}$. That is, it is all the elements in the
domain that are mapped to elements in $B$.
(A) For $f: \mathbb{N} \to \mathbb{N}$ defined by $f(n) = n^2$, what are each of
the following sets?
(a) $f^{-1}(\{1, 4, 9\})$
(b) $f^{-1}(\{2, 3, 5, 7\})$
\(c\) $f^{-1}(\{1, 2, \dots, 10\})$
(B) Prove that for any set $C \subseteq X, C \subseteq f^{-1}(f(C))$.
\(C\) Give an example of a function $f$ and a set $C$ such that
$C \neq f^{-1}*(f(C))$.
(D) Prove that for any set $D \subseteq Y, f(f^{-1}(D)) \subseteq D$.
(E) Give an example of a function $f$ and a set $D$ such that
$f(f^{-1}(D)) \neq D$.
A:
10.
Q: Let $f: X \to Y$ be a function, and let $A$ and $B$ be subsets of $Y$. Prove
that $f^{-1}(A \cap B) = f^{-1}(A) \cap f^{-1}(B)$.
A:
11.
Q: Let $f: X \to Y$ be a function, and let $A$ and $B$ be subsets of $Y$. Prove
that $f^{-1}(A \cup B) = f^{-1}(A) \cup f^{-1}(B)$.
A:
12.
Q: For each relation below, determine whether it is transitive. If it is, prove
it. If it is not, give a counterexample.
(a) The relation "$|$" (divides) on $\mathbb{Z}$ defined by $a|b$ provided $b$
is a multiple of $a$.
(b) The relation "$\leq$" (less than or equal to) on $\mathbb{R}$.
\(c\) The relation "$\perp$" (is perpendicular to) on the set of lines in the
plane.
(d) The relation "$\sim$" (is similar to) on the set of triangles in the plane
(two triangles are similar if they have the same angles, bu are not necessarily
the same size).

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# Definition 1.5.1
A set $A$ is a **subset** of a set $B$, written $A \subseteq B$, provided every
element of $A$ is also an element of $B$.
The set $B$ is sometimes called a **superset** of $A$.
We say $A$ is a **proper subset** of $B$, written $A \subset B$, provided
$A \subseteq B$ and $A \neq B$. In other words, if every element in $a$ is an
element in $B$, and there is at least one element in $B$ that is _not_ in $A$.
## Example 1.5.2
Let $A = \{x \in \mathbb{N}: x < 5\}$ and $B = \{x \in \mathbb{N}: x^2 < 10\}$.
Is $B \subseteq A$? Is $B$ a _proper_ subset of $A$?
**Solution** We are asking whether every natural number less than $5$ is also a
natural number whose square is less than $10$. Okay, we could just write out the
elements of the sets: $A = \{0, 1, 2, 3, 4\}$ and $B = \{0, 1, 2, 3\}$ (since
$3^2 = 9$ and $4^2 = 16$) . So $B \subseteq A$. But $B \neq A$, so in fact
$B \subset A$.

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# Definition 1.5.12
A relation $R$ on a set $A$ is **transitive** provided for all $x$, $y$,
$z \in A$, if $xRy$ and $yRz$, then $xRz$.
## Example 1.5.13
Consider the relation $~$ on the set of students in your Discrete Math course
that holds of two students, provided they have some other class together. Is
this relation transitive?
**Solution** No, not necessarily (although for some sets of students it could
be). For example, suppose Alice has another class with Bruce, say Introduction
to Programming. Carlos is not in Intro to Programming, but he and Bruce are both
in Organic Chemistry. So then Alice $~$ Bruce and Bruce $~$ Carlos, but it might
nobe the case that Alice $~$ Carlos (since Alice need not be in Organic
Chemistry with Carlos).

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# Definition 1.5.15
Let $v$ be a vertex in a graph $G$. The **degree** of $v$, written $d(v)$, is
the number of edges that contain $v$, i.e., the number of edges **incident** to
$v$.

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# Definition 1.5.5
A function $f : A \to B$ is **injective** (or **one-to-one**) provided every
element in$ B$ is the image of at most one element in $A$. In other words, no
element in $B$ is the _output_ for more than one _input_ from $A$.

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# Definition 1.5.9
Given a function $f : X \to Y$ and a set $A \subseteq X$, we define the **image
of** $A$ **under** $f$ to be the set $f(A) = \{f(a) \in Y: a \in A\}$. That is,
$f(A)$ is the set of all outputs of the function for inputs in $A$.
## Example 1.5.10
Let $f: \mathbb{N} \to \mathbb{N}$ be defined by $f(n) = 2n$. Let
$A = \{1, 2, 3\}$. Find $f(A)$.
**Solution**. Evaluate each element of $A$ by $f$.
$$ f(1) = 2; \quad f(2) = 4; f(3) = 6. $$
We want the set of these outputs. So $f(A) = \{2, 4, 6}$.

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# 1.5.7 Practice Problems
1.
Q: Given sets $A$ and $B$, the **intersection** of $A$ and $B$, written
$A \cap B$, is the set of all elements that are in both $A$ and $B$.
Suppose you wanted to prove that if $A \cap B = B$ then $B \subseteq A$.
Which would be a good start to this proof if you used a direct proof?
A. Let $a$ be an element of $A \cap B$.
B. Let $b$ be an element of $B$.
C. Let $a$ be an element of $A$.
D. Suppose there is an element $b$ in $B$ that is not in $A$.
A:
2.
Q: Suppose you wanted to prove that for all sets $A$ and $B$ that
$A \cap B \subseteq A$. Which of the following would be a good start to a proof
by contradiction?
A. Suppose there is an element $a$ in $A$ that is not in $A \cap B$.
B. Suppose there is an element $a$ in $A \cap B$ that is not in $A$.
C. Let $a$ be an element of $A$.
D. Let $a$ be an element of $A \cap B$.
A:
3.
Q: Arrange some of the statements below to form a correct proof of the following
statement: "For any sets $A$ and $B$, if $B \subseteq A \cap B$" then
$B \subseteq A$".
- Therefore $B \subseteq A \cap B$
- Since $A \cap B$ contains all the elements that are in both $A$ and $B$, $b$
is an element of $A$.
- Then $b$ is an element of $A \cap B$ since $B \subseteq A \cap B$.
- Let $b$ be an element of $A \cap B$.
- Suppose $B \subseteq A$.
- Suppose $B \subseteq A \cap B$, then let $b$ be an element of $B$.
- Then $b$ is an element of $B$ since $B \subseteq A \cap B$.
- Therefore $B \subseteq A$.
- Suppose $A \subseteq B$.
A:
4.
Q: Prove that for any sets $A$ and $B$, $(A \cap B) \cup A$ = A$. Arrange the
statements below to form a correct proof.
- So in particular, $x$ is an element of $A$.
- Second, we will prove that $A \subseteq (A \cap B) \cup A$.
- Let $x$ be an element of $(A \cap B) \cup A$.
- Therefore $A \subseteq (A \cap B) \cup A$.
- First we will prove that $(A \cap B) \cup A \subseteq A$.
- Therefore $(A \cap B) \cup A \subseteq A$.
- Since $(A \cap B) \cup A \subseteq A$ and $A \subseteq (A \cap B) \cup A$, we
have $(A \cap B) \cup A = A$.
- Then $x$ is an element of $(A \cap B) \cup A$, since $x$ is in $A$ or in the
other set.
- Then $x$ is an element of $A \cap B$, or $x$ is an element of $A$.
- Let $x$ be an element of $A$.
A:
5.
Q: Let $f: X \to Y$ be a function and let $B \subseteq Y$ be a subset of the
codomain. Define the **inverse image** of $B$ under $f$ to be the set
$f^{-1}(B) = \{x \in X: f(x) \in B\}$. That is, it is all the elements in the
domain that are mapped to elements in $B$.
Prove that if $B_1 \subseteq B_2$ are subsets of the codomain, then
$f^{-1}(B_1) \subseteq f^{-1}(B_2)$. Arrange some of the statements below to
form a correct proof.
- Thus $B_1 \subseteq B_2$ .
- This means that $f(a)$ is an element of $B_1$.
- Therefore $b$ is an element of $B_2$.
- Therefore $f^{-1}(B_1) \subseteq f^{-1}(B_2)$.
- Suppose $B_1 \subseteq B_2$.
- Since $B_1 \subseteq B_2$, $f(a)$ is an element of $B_2$.
- This then means that $a$ is an element of $f^{-1}(B_2)$.
- Let $b$ be an element of $B_1$.
- Let $a$ be an element of $f^{-1}(B_1)$.
A:

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@ -14,31 +14,80 @@ in $A$ is also an element of $B$.
b. Given sets $A$ and $B$, the union of $A$ and $B$, written $A \cup B$, is the
set containing every element that is in $A$ and $B$ or both.
(a) Let $B = \{1, 3, 5, 7, 9\}$. Give an example of a set $A$ containing 3
(a)
Q: Let$B = \{1, 3, 5, 7, 9\}$. Give an example of a set $A$ containing 3
elements that is a subset of $B$.
What is $A \cup B$ for a set $A$ you gave as an example?
(b) Give an example of two distinct sets $A$ and $B$ such that $A \cup B = B$.
A:
$$ A = \{1, 3, 5\} $$
$$ A \cup B = \{1, 3, 5, 7, 9\} $$
(b)
Q: Give an example of two distinct sets $A$ and $B$ such that $A \cup B = B$.
For the example you gave, is $A \subseteq B$?
\(c\) Find examples, if they exist, of sets $A$ and $B$ such that
A:
$$ A = \{1, 2\}, \quad B = \{1, 2, 3\} $$
Yes, for this example, $A \subseteq B$.
\(c\)
Q: Find examples, if they exist, of sets $A$ and $B$ such that
$A \cup B \neq B$.
For the example you gave, is $A \subseteq B$?
A:
$$ A = \{1, 2, 3\} \quad B = \{1, 2\} $$
$$ A \cup B = \{1, 2, 3\} $$
In this case $A$ is not a subset of $B$.
2.
Which of the following are always true?
A. For any sets $A$ and $B$, $A \cup B \subseteq B$.
A.
B. For any sets $A$ and $B$, $B \subseteq A \cup B$.
Q: For any sets $A$ and $B$, $A \cup B \subseteq B$.
C. For any sets $A$ and $B$, if $A \subseteq B$, then $A \cup B \subseteq B$.
A: No, we just demonstrated that this was not true in 1a by showing example sets
this is not the case.
D. For any sets $A$ and $B$, if $A \cup B = B$, then $A \subseteq B$.
B.
Q: For any sets $A$ and $B$, $B \subseteq A \cup B$.
A: Yes this is always true. Since $A \cup B$ will always contain elements from
both $A$ and $B$, this means that every element of $B$ is automatically in
$A \cup B$.
C.
Q: For any sets $A$ and $B$, if $A \subseteq B$, then $A \cup B \subseteq B$.
A: Yes this is always true. $A \subseteq B$ means that set $B$ contains all
elements of $A$, and so therefore the union of $A \cup $B$ will always be a
subset of $B$.
D.
Q: For any sets $A$ and $B$, if $A \cup B = B$, then $A \subseteq B$.
A: Yes, this is always true. If $A \cup B = B$, this means that any element in
$A$ must also be in $B$, but $A$ must also not contain any elements not in $B$.
This makes $A$ a subset of $B$.
3.
@ -50,10 +99,45 @@ $f(A) = \{f(x) : x \in A\}$.
For the following tasks, let's explore the function
$f : \mathbb{N} \to \mathbb{N}$ defined by $f(x) = x^2 - 3x + 8$.
(a) Let $A = \{1, 2, 3\}$ and $B = \{2, 4, 6\}$. Find $f(A)$ ad $f(B)$. Then
find $f(A) \cup f(B)$.
(a)
Q: Let $A = \{1, 2, 3\}$ and $B = \{2, 4, 6\}$. Find $f(A)$ ad $f(B)$. Then find
$f(A) \cup f(B)$.
A:
$$ f(A) = \{6, 8 \} $$
$$ f(B) = \{12, 26\} $$
$$ f(A) \cup f(B) = \{6, 8, 12, 26\} $$
(b) Now find $A \cup B$ and $f(A \cup B)$.
\(c\) Give an example, if one exists, of two distinct sets $A$ and $B$ such that
$$ A \cup B = \{1, 2, 3, 4, 6\} $$
$$ f(A \cup B) = \{6, 8, 12, 26\} $$
\(c\)
Q: Give an example, if one exists, of two distinct sets $A$ and $B$ such that
$A \subseteq B$ and $f(A) \subseteq f(B)$.
A:
$$ A = \{1, 2\} \quad B = \{1, 2, 3\} $$
$$ A \subseteq B $$
$$ f(A) = \{6\} $$
$$ f(B) = \{6, 8\} $$
$$ f(A) \subseteq f(B) $$
Q: Give an example, if one exists, of two distinct sets $A$ and $B$ such that
$A \subseteq B$ but $f(A) \nsubseteq f(B)$.
A:
The requested example cannot exist.

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# Proposition 1.5.11
Let $f: X \to Y$ be a function, and let $A$ and $B$ be subsets of $X$. If
$A \subseteq B$, then $f(A) \subseteq f(B)$.

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# Proposition 1.5.17
In any graph, the number of vertices with odd degree must be even.

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# Proposition 1.5.3
For any sets $A$, $B$, and $C$, if $A \subseteq B$ and $B \subseteq C$, then
$A \subseteq C$.

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# Proposition 1.5.7
Suppose $f : A \to B$ is a function with $A$ and $B$ both finite sets. If
$|A| > |B|$, then $f$ is not injective.

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# 1.5.6 Reading Questions
1.
Q: Which of the following is the definition of a function $f: A \to B$ being
injective?
A. Every element of $B$ is the image of at most one element of $A$.
B. The domain $A$ is a larger set than the codomain $B$.
C. Every element of $A$ is sent to at most one element of $B$.
D. The codomain $B$ is no smaller than the domain $A$.
A:
2.
Q: When would you most likely use element chasing as part of a proof?
A. When proving that one set is a subset of another.
B. When proving that a function is injective.
C. When proving that a relation is transitive.
D. When proving that a graph has an odd number of edges.
A: